Tính: a) (x^2 – 2x + 1) : (x – 1) ; b) ( x^3 + 2x^2 + x ) : (x^2 + x)

Câu 3 trang 59 vở bài tập Toán lớp 7 Tập 2:

a) (x2 – 2x + 1) : (x – 1)

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b) ( x3 + 2x2 + x ) : (x2 + x)

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c) ( –16x4 + 1) : (–4x2 + 1)

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d) ( –32x5 + 1) : ( –2x + 1)

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Lời giải:

a) ( x2 – 2x + 1 ) : ( x – 1 )

Tính: a) (x^2 – 2x + 1) : (x – 1) ; b) ( x^3 + 2x^2 + x ) : (x^2 + x)  (ảnh 625)
Vậy (x2 – 2x + 1) : ( x – 1 ) = x – 1.

b) ( x3 + 2x2 + x ) : ( x2 + x )

Tính: a) (x^2 – 2x + 1) : (x – 1) ; b) ( x^3 + 2x^2 + x ) : (x^2 + x)  (ảnh 631)
Vậy ( x3 + 2x2 + x ) : ( x2 + x ) = x + 1.

c) ( –16x4 + 1) : ( –4x2 + 1)

Tính: a) (x^2 – 2x + 1) : (x – 1) ; b) ( x^3 + 2x^2 + x ) : (x^2 + x)  (ảnh 641)
Vậy ( –16x4 + 1) : ( –4x2 + 1) = 4x2 + 1.

d) ( –32x5 + 1) : ( –2x + 1)

Tính: a) (x^2 – 2x + 1) : (x – 1) ; b) ( x^3 + 2x^2 + x ) : (x^2 + x)  (ảnh 635)
Vậy ( –32x5 + 1) : (–2x + 1) = 16x4 + 8x3 + 4x2 + 2x + 1.

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